baconandeggs
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Post by baconandeggs on Oct 11, 2012 18:23:20 GMT
Use a bolt wrap the wire around the threads and unscrew the bolt leaving a perfect coil
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Moon
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Post by Moon on Oct 11, 2012 21:04:08 GMT
Use a bolt wrap the wire around the threads and unscrew the bolt leaving a perfect coil This is something that I may well try. I'll give it a go with a drill bit first, as I have a good few small ones and see how I get on with that method. It won't be as perfect but I'll have a fanny around with a cocktail stick.
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FirinBlanks
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Post by FirinBlanks on Oct 11, 2012 22:08:25 GMT
'Ahem. This is my theory, what it is...' (Name that sketch ) Peter Sellars The Goon Show I'm not sure what episode though, but I listened to it recently (if that helps)?
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Post by domesticextremist on Oct 12, 2012 8:42:58 GMT
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FirinBlanks
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Post by FirinBlanks on Oct 12, 2012 11:02:57 GMT
Curses! It must have been the male high pitched voice thing that threw me, both are equally fab in my eyes though (if that helps to dig me out of the hole).
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spike74656
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Post by spike74656 on Oct 13, 2012 22:50:14 GMT
I'm Afraid I'm going to have to be a pain and point out that your formula doesnt take into account different voltages.
The heat generated isn't about the resistance it is about the amps. So you would need to factor in V = IR and the power drain is about the wats for which you would need P=IV Or P=Isquared R.
And then of course there are the thermal properties of the wire, How hot it can get before it starts to do strange things like melt and break.
V = Voltage I = Current R = Resistance P = Power
Of course we must ask just how accurate do we really need to be, especially if we are using variable voltage batteries that we can just tweak up and down. Not to mention if we are measuring the resistance how many of us have regularly calibrated meters with an accuracy greater than + or - 1% down on the ten Ohm range?
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spike74656
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Post by spike74656 on Oct 13, 2012 22:52:37 GMT
To clarify my previous post, Resistance does play a part along with length/type of wire but the amps are the easiest way to look at the heat generated.
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Brian
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Post by Brian on Oct 14, 2012 0:46:41 GMT
I understand "Im afraid", but the rest went whoosh, straight over my head!
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Post by domesticextremist on Oct 14, 2012 8:01:11 GMT
I'm Afraid I'm going to have to be a pain and point out that your formula doesnt take into account different voltages. The heat generated isn't about the resistance it is about the amps. So you would need to factor in V = IR and the power drain is about the wats for which you would need P=IV Or P=Isquared R. And then of course there are the thermal properties of the wire, How hot it can get before it starts to do strange things like melt and break. V = Voltage I = Current R = Resistance P = Power Of course we must ask just how accurate do we really need to be, especially if we are using variable voltage batteries that we can just tweak up and down. Not to mention if we are measuring the resistance how many of us have regularly calibrated meters with an accuracy greater than + or - 1% down on the ten Ohm range? Be as much of a pain as you like However, neither the current nor the voltage are affected by the dimensions of the coil - they are determined by the power source. The point of the thread is to answer the question of how many turns does one need to achieve a target resistance, that's all.
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spike74656
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Post by spike74656 on Oct 14, 2012 10:22:14 GMT
Well the dimensions of the coil determine the resistance, which in turn does affect the current assuming the power source remains the same.
But fair point it doesnt need to be considered if you are only looking for number of turns for target resistance.
The best way I have seen of doing this is to just measure the wire before cutting it and then add a length of no res wire either side. You then only coil the resistive wire around the wick and take the no res wire to the connections then you have the exact resistance you want. But I would have to agree that its a bit of a faff.
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