jevans
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Post by jevans on Jul 11, 2017 7:08:38 GMT
Even with regulated Mods, Watts still = Current squared x Ohms. Thus the higher the Ohms, the lower the current, the longer the battery lasts!
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Greg
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Post by Greg on Jul 11, 2017 10:08:14 GMT
Even with regulated Mods, Watts still = Current squared x Ohms. Thus the higher the Ohms, the lower the current, the longer the battery lasts! And there's the misconception right there that VapingBad speaks of. In a mech mod the power is determined by the resistance (and the battery voltage) , in a regulated mod the power is determined by the setting you request and the electronics adjust the voltage to deliver the power you've set. so 70 watts is 70 watts regardless of what resistance you use on a regulated mod, ignoring the electronics efficiency losses of course.
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jevans
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Post by jevans on Jul 11, 2017 11:46:06 GMT
Even with regulated Mods, Watts still = Current squared x Ohms. Thus the higher the Ohms, the lower the current, the longer the battery lasts! And there's the misconception right there that VapingBad speaks of. In a mech mod the power is determined by the resistance (and the battery voltage) , in a regulated mod the power is determined by the setting you request and the electronics adjust the voltage to deliver the power you've set. so 70 watts is 70 watts regardless of what resistance you use on a regulated mod, ignoring the electronics efficiency losses of course. Not so Greg! No matter what the power source...W=I 2R Which means that if you change "R" you also have to change "I" to maintain the same set Wattage! ETAMod set at 20W with 1.2 Ohm coil = 4.1 Amps " " " " with 0.5 Ohm coil = 6.3 Amps
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VapingBad
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Post by VapingBad on Jul 11, 2017 18:49:43 GMT
And there's the misconception right there that VapingBad speaks of. In a mech mod the power is determined by the resistance (and the battery voltage) , in a regulated mod the power is determined by the setting you request and the electronics adjust the voltage to deliver the power you've set. so 70 watts is 70 watts regardless of what resistance you use on a regulated mod, ignoring the electronics efficiency losses of course. Not so Greg! No matter what the power source...W=I 2R Which means that if you change "R" you also have to change "I" to maintain the same set Wattage! ETAMod set at 20W with 1.2 Ohm coil = 4.1 Amps " " " " with 0.5 Ohm coil = 6.3 Amps No, the battery in not directly connected to the coil it has an active circuit between them, think in Watts on both sides of the board, you would work out the battery current by power * (100 / efficiency) / battery voltage so say at 50 W with 80% efficiency converter 50 * 100/80 / battery voltage = 62.5 / battery voltage so with a low battery 3 V current would be 20.8 A with a fullish battery 4 V current would be 15.6 A
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jevans
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Post by jevans on Jul 11, 2017 19:37:18 GMT
Not so Greg! No matter what the power source...W=I 2R Which means that if you change "R" you also have to change "I" to maintain the same set Wattage! ETAMod set at 20W with 1.2 Ohm coil = 4.1 Amps " " " " with 0.5 Ohm coil = 6.3 Amps No, the battery in not directly connected to the coil it has an active circuit between them, think in Watts on both sides of the board, you would work out the battery current by power * (100 / efficiency) / battery voltage so say at 50 W with 80% efficiency converter 50 * 100/80 / battery voltage = 62.5 / battery voltage so with a low battery 3 V current would be 20.8 A with a fullish battery 4 V current would be 15.6 A You cannot re-write Ohms law! The only way your theory can be true is if the Watts display is telling porkies! WATTS = I 2R and will always do so! WATTS = IV " WATTS = V 2/R "
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jtc
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Post by jtc on Jul 11, 2017 20:15:50 GMT
This is interesting If a DNA mod was plugged into escribe and fired, wouldn't this show who to be correct? 🤔
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Postmodern Smoking
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Post by Postmodern Smoking on Jul 11, 2017 20:20:14 GMT
The current and voltage from the battery are different from the current and voltage through the coil (because of regulating electronics). [ETA] Unlike the simple mech mod that doesn't have any active components:
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VapingBad
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Post by VapingBad on Jul 11, 2017 20:31:30 GMT
No, the battery in not directly connected to the coil it has an active circuit between them, think in Watts on both sides of the board, you would work out the battery current by power * (100 / efficiency) / battery voltage so say at 50 W with 80% efficiency converter 50 * 100/80 / battery voltage = 62.5 / battery voltage so with a low battery 3 V current would be 20.8 A with a fullish battery 4 V current would be 15.6 A You cannot re-write Ohms law! The only way your theory can be true is if the Watts display is telling porkies! WATTS = I 2R and will always do so! WATTS = IV " WATTS = V 2/R " That's not even in Ohm's law, it's from Joule Heating of a resistive load. You do not have a passive resistive load attached to a battery, you have an active voltage converter between the battery and the coil so you are not applying Ohm's correctly because there a lot more in the circuit than a simple resistive load. You would be breaking the First Law of Thermodynamics by creating or destroying energy, it can only be converted in this universe. Google boost or buck voltage converters if you want detail.
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bobby00
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Post by bobby00 on Jul 11, 2017 20:34:34 GMT
Thanks fellas I've tested them all and bought an app that tells me what I need to do I just put wire size in and how many watts I want and it tells so I'm Golden>
I think its all flavour for me I've lost 7lb since I started vaping no sweeties so very happy! Better than weight watchers lol
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bobby00
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Post by bobby00 on Jul 11, 2017 20:38:40 GMT
Wow really set the fox loose in the hen house PEACE brothers!!!
I only wanted a above ohm coil not a war
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VapingBad
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Post by VapingBad on Jul 11, 2017 20:40:30 GMT
This is interesting If a DNA mod was plugged into escribe and fired, wouldn't this show who to be correct? 🤔 No, but I wouldn't have got my Bachelors of Engineering in Electronics & Management if I was wrong about such basic concepts, sadly this a widely held belief that Jim is talking about far too many youtube and self appointed vaping experts repeat it all the time It's not surprising lot's people for getting mislead. Like this stupid sub-ohm phrase it is really not making vapers lives easier and those who have a platform should not keep spreading this sort of rubbish.
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VapingBad
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Post by VapingBad on Jul 11, 2017 20:43:52 GMT
Wow really set the fox loose in the hen house PEACE brothers!!! I only wanted a saboteur ohm coil not a war Don't worry about it I will point out this stuff as it impacts on safety and using the wrong maths is far worse than not using any, so fell I have no option. Don't worry about the ohms over much just be between the min and max your mod supports.
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jtc
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Post by jtc on Jul 11, 2017 21:49:35 GMT
Well I'm using a 0.13 ohm ss clapton coil at 50w and my battery life is great. Probably as it heats up so quickly being ss 😊😉😄
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jevans
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Post by jevans on Jul 12, 2017 0:34:20 GMT
You cannot re-write Ohms law! The only way your theory can be true is if the Watts display is telling porkies! WATTS = I 2R and will always do so! WATTS = IV " WATTS = V 2/R " That's not even in Ohm's law, it's from Joule Heating of a resistive load. You do not have a passive resistive load attached to a battery, you have an active voltage converter between the battery and the coil so you are not applying Ohm's correctly because there a lot more in the circuit than a simple resistive load. You would be breaking the First Law of Thermodynamics by creating or destroying energy, it can only be converted in this universe. Google boost or buck voltage converters if you want detail. I DO have a passive resistive load connected to a power source. X watts will be produced when Y amps flow. You cannot alter that no matter what your power source is!
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VapingBad
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Post by VapingBad on Jul 12, 2017 5:23:03 GMT
But the battery cannot see that passive load it has a black box active electronic circuit between them jevans If you have a 1 ohm coil, 80% effiency and 4 V battery at 10 W and a 0.5 ohm coil at the same levels they would both draw 3.125 A as they are using 12.5 W from a 4 V battery. If they drew different currents the wattages would be different, you would have created or destroyed energy breaking the First Law of Thermodynamics, one of the fundamental Laws of Nature. You are confusing this the situation on the coil side where at 10 W the 1 ohm coil would need 10 V and draw 1 A and the 0.5 ohm would need 5 V at 2 A. Look at a wall-walt power supply and note the DC ampage and the Mains AC ampages are different.
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