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I know peeps have been sub0uming for years now, and over that time the batteries have improved so much things like the IR and Volt drop have become a concern.

However there's an emergence of newer cells with much higher IR.

AWT have a 20/35Amp battery with an IR better than 0.08 Ohms. So better could mean 0.079 Ohms. Draw 20Amps from that and we get a calculated 3.05 Volts at the battery's terminals.

I'm not denying the resistance of the whole mod will reduce this drop, but at what point will a cell become useless (and dangerous).

The AWT I've been testing will only deliver 52.2 Amps through a dead short - maybe that's what the makers believe will make them safer batteries.

batteryuniversity.com/learn/article/how_does_internal_resistance_affect_performance
batteryuniversity.com/learn/article/rising_internal_resistance

And a calculator: hyperphysics.phy-astr.gsu.edu/hbase/electric/dcex6.html

Of course if we want to make it more difficult we could throw in the various other resistances. However it's easier to consider them as negligible because as they rise the current draw will be reduced even more.

Added, thank you

No need for apologies, just pop over and say hi: allaboute-cigarettes.proboards.com/board/22/absolute-beginners-new-members

Wizardry is where many peeps go wrong. I value your input hijack, raising some questions others aren't asking

No 'dark ages' to it, unless you want to step back about 10 years

Using pure maths a VTC5/4/3 would be capable of over 100Watts, but we have to take into consideration the IR of the battery and the joints/wires within the mod.

A simple method for regulated mods is to consider the battery's voltage as 2.5Volts. This will allow for battery drain and Volt drops.

so - 30x2.5 = 75Watts (2.5Volts takes into consideration a drained battery and the Volt drop)

I'm not intending to treat anyone as dumb, just taking the maths out of it all to make it easier to get the head around

You have to admit hijack, as rated outputs of batteries get higher the IR becomes all the more important (especially with one company pushing a 20Amp (quoted 35Amp) battery with an IR of less that 0.08Ohms (DC)). Using V=IR we see that 20x0.08=1.6Volts. A freshly charged battery could easily drop to 2.6Volts when fired.

The offender in this case is AWT, but seeing how easy it is to push such batteries is BLOODY FRIGHTENING!!!!!